A series LCR circuit containing a resistance of 120 Ω has angular resonance frequency 4 × 10 5 rads –1 . At resonance the voltage across resistance and inductance are 60 V & 40 V respectively. At what frequency the current in the circuit lags the voltage by 45°. Give answer in -------×10 5 rad/sec.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(8)
At resonance reactance = 0
I = 
= 
= 
Amp.
V L = I × X L = I × ω L
∴ L = 
………(i)
ω 0 = 
C = 
…….(ii)
Calculate L & C from (1) & (2) current will lag
the applied voltage by 45°
if tan 45° = 
Solve for ω
ω = 8 × 10 5 rad/sec
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